1. if root 1-x6 + root 1-y 6 = a3(x3-y3). prove dy/dx = x2/y2*wholeroot 1-y6/1-x6

Proof:  Putting x3 = sin A and y3 = sin B in the given equation, we get

Differentiating both sides w.r.t x, we get

Hence Proved

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