if root 3 tan theta = 3 sin theta, then ( sin2 thea - cos2 theta) = ??
since root 3 tan theta = 3sin theta
so, root 3 son theta /cos theta= sin theta
= so, root 3 will cut 3 and sin theta wil be cancelled
= so, 1/cos theta= root3
so, cos theta =1/root 3
so, squaring on both sides:
=cos2theta= 1/3
let it be equation no. 1
= 1-sin2theta= 1/3
=sin 2 theta=1-1/3
= sin2theta=2/3
let it be equation no. 2
so, on subtracting equation 1 from 2:
sin2theta - cos2theta = 22/32 - 12/32
= 4/9 - 1/9
= 3/9 = 1/3 that is the answer.
i hope you may be satisfied with my answer.
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