if sec theta+tan theta+1= 0,then find sec theta -tan theta
sec theta + tan theta +1 =0
sec theta + tan theta = -1 ..............(1)
we know that sec2 - tan 2 = 1
therfore (sec+tan)(sec-tan) = 1
-1(sec-tan) = 1..........(from 1)
sec-tan=1/-1
therefore sec-tan=-1
Hope it helps.......Cheers!!!
sec theta + tan theta = -1 ..............(1)
we know that sec2 - tan 2 = 1
therfore (sec+tan)(sec-tan) = 1
-1(sec-tan) = 1..........(from 1)
sec-tan=1/-1
therefore sec-tan=-1
Hope it helps.......Cheers!!!