if siny= xsin(a+y),then prove that dy/dx=sin^2(a+y)/sin a Share with your friends Share 12 Varun.Rawat answered this We have,x= sin y sin a+y⇒dxdy = sina + y . cos y - sin y cos a+ysina + y2 quotient rule ⇒dxdy =cos y [sin a cos y + cos a sin y] - sin y[cos a cos y - sin a sin y]sin2a + y⇒dxdy =sin a cos2y + cos a sin y cos y - cos a sin y cos y + sin a sin2ysin2a + y⇒dxdy = sin a cos2y + sin a sin2y sin2a + y⇒dxdy = sin a cos2y + sin2ysin2a + y⇒dxdy =sin asin2a + y⇒dydx = sin2a + ysin a 89 View Full Answer Rajan Gupta answered this siny=xsin(a+y)siny / sin(y+a) = xon differentiation we get..dy / dx (cosy.sin(a+y) - cos(a+y).siny)/sin^2(a+y) = 1on simplification, using sin(a+b) formula,the result will be obtained 0