if the activation energy of forward and backward reactions in a chemical reaction A--->B is 15.5 and 22.7 kj mol-1 respectively then select the correct option for the reaction 

1) delta H of reaction is 38.2 KJ/mol
2) Reaction is always spontaneous 
3) Decreaseing the activation energy
4) Decreasing the rate constant
 

Dear Student,
Given: Eaforward = 15.5 KJ/mole 
Ea​Backward = 22.7 KJ/mole 

H=Eaforward-EabackwardH= 15.5-22.7H= 
since the activation energy of forward is less than the activation energy of backward then the reaction will be spontaneous.
hence option (b) is the correct answer
 

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