if the area of an isosceles right triangle is 8cm,what is its perimeter
Let, base= x
AS an isoceles right triangle 2 sides are same so hight is also x.
Area= 1/2 x base x height
8cm=1/2 x base x height
8x2= XxX
16=x2
square root of 16 = x
4cm = x (x = base and height)
By pythagoras therom,
AC2 = AB2 + BC2
= (4)2 + (4)2
= 16 + 16
= 32 cm
AC = square root of 32
AC = 4 root 2 cm
Perimof the triangle = x + x + x
= 4+4+4 root 2
= 8+ 4 root 2