IF THE AREAS OF TWO SIMILAR TRIANGLES ARE EQUAL,,PROVE THAT THEY ARE CONGRUENT...

 let, triangle abc and triangle pqr be similar and equal area.

area(abc)/area(pqr) = ab/pq  (theorem)

area(abc)/area(abc) = ab/pq

1=ab/pq

ab=pq

similarly

bc=qr

ac=pr

by sss congruency rule triangle abc is congruent to triangle pqr

thumbs up plzz

sorry its ab² and pq² in the second line. if u take square root  it would become ab and pq