If the child weighs 20kg and if the lift is
moving down with a uniform acceleration
of 5ms^ -2, what will be the apparent weight
of the child?
Dear student,
Given, a = 5m/s2
m = 20kg
Now weight = m g
apparent weight, w = m (g-a) N [because lift is moving downwards]
= 20 (9.8-5)
=96 N
Regards