If the mth term of an A.P. be 1/n and nth term be 1/m, then show that its (mn)th term is 1.

 

Hi!
Here is the answer to your question.
 
Let a and d be the first term and common difference of A.P.
 

For answer of other query we request you to kindly post other question in different thread so that we can help you in better way.

 

  • 447

 Hey,,,,,,,

Tm = 1/n    &      Tn = 1/m

a +(m-1)d = 1/n

a + (n-1)d = 1/m

-------------------------

(m-n)d = m-n/mn

d = 1/mn  ,     & a = 1/mn

now , Tmn = a +(mn-1)d = 1/mn +(mn-1) x 1/mn

                                              =1 +mn-1 / mn = mn/mn = 1.....hence prooved!!

hope ths hlps u ..!!

  • 78
What are you looking for?