IF the points A(6,1), B(8,2), C(9,4) and D(p,3) are the vertices of a parallelogram taken in order. Find the value of p.

Is this answer right

AB=CD

AB

^{2}=CD^{2}(6-8)+(1-2)=(9-P)+(4-3)

4+1=81-18+P

^{2}+1P

^{2 }-18p+77=0p

^{2}-11p-7p+77=0p(p-11)-7(p-11)=0

(p-7) (p-11)=0

p=7,11

well but 11 here is not right

i tried it in graph & only 7 seems to be correct!

can somebody tell me why is 11 not correct (as it is mathematically correct)

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