If the radius of the earth shrinks by 2.5 % mass remaining constant. Then how would the value of acceleration due to gravity change?
Dear Student

g= GM/R2 ......(1)
g=Acc. due to gravity , M- mass of the earth R-Radius of the Earth
Differentiating it, we have dg= -2GM/R3 * dR ........(2)
Dividing (2) by (1) ,
dg/g = -2dR/R .....(3)
Given radius of the earth shrinks by 2.5% ,
dR/R = -2.5/100
From (3)
% increase in the value of g is ----- dg/g *100 = -2dR/R *100
= -2 [ -2.5/100] *100
= 5%
So the value of acceleration due to gravity increases by 5%.
Regards