if the zeroes of the polynomial x2 + px + q are double in value to the zeroes of 2x2 - 5x - 3 ,then find the value of p and q

2x2 - 5x - 3

2x2 - 6x +1x -3

2x (x - 3) +1 (x - 3)

(x - 3) (2x+1)

x = 3, x = -1/2

so, zeroes of x2 +px+q are 2*3 = 6 and 2 * -1/2 = -1

let the zeroes be a = 6 and b = -1

a+b = -coefficient of x/coefficient of x2

6 + (-1) = -p/1

5 = -p

p = -5

a*b = constant term/coefficient of x2

6 * (-1) = q/1

q = -6

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thanks shriya sharma for this wonderful answer

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