If theta is an acute angle and tan theta + cot theta = 2 , then value of tan^7 theta + cot^7 theta is ?
Given : tan θ + cot θ = 2
Thus, tan7θ + cot7θ = tan745° + cot745° = (tan 45°)7 + (cot 45°)7= 17 + 17 = 1 + 1 = 2
If theta is an acute angle and tan theta + cot theta = 2 , then value of tan^7 theta + cot^7 theta is ?
Given : tan θ + cot θ = 2
Thus, tan7θ + cot7θ = tan745° + cot745° = (tan 45°)7 + (cot 45°)7= 17 + 17 = 1 + 1 = 2