if three consecutive multiples of 11 are multiplied by 2,3 and 4 respectively and then added ,the sum is 814 .find each of the multiples? Share with your friends Share 8 Lovina Kansal answered this Dear student Let the consecutive multiples of 11 be 11x,11(x+1) and 11(x+2)Then, According to question,211x+311x+1+411x+2=81422x+33x+33+44x+88=81499x=693x=7Therefore, each of the multiple is 11x=11×7=7711(x+1)=11(7+1)=88and 11(x+2)=11(7+2)=99 Regards 2 View Full Answer