# If three different coins are tossed together, then find the probability of getting two heads.

We know , Probability P ( E ) = $\frac{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{desired}\mathrm{events}\mathrm{n}(\mathrm{E})}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{events}\mathrm{n}(\mathrm{S})}$

We know when 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.

Total number of possible outcomes = 8 , So

n ( S ) = 8

Here we can see that there three outcomes = HHT, HTH and THH where we get " two " heads , So

n ( E ) = 3

Then,

Probability of getting two heads = $\frac{\mathbf{3}}{\mathbf{8}}$

Hope this information will clear your doubts about topic.

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