If three different coins are tossed together, then find the probability of getting two heads.

Please find below the solution to the asked query:

We know , Probability P ( E )  = $\frac{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{desired} \mathrm{events} \mathrm{n} ( \mathrm{E} )}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{events} \mathrm{n} ( \mathrm{S} )}$


We know  when 3 coins are tossed simultaneously, the possible outcomes are HHH, HHT, HTH, THH, THT, HTT, TTH and TTT.
 Total number of possible outcomes = 8 , So

n ( S ) =  8

Here we can see that there three outcomes = HHT, HTH and THH  where we get " two " heads , So

n ( E ) =  3 

Then,

Probability of getting two heads = $\frac{\mathbf{3}}{\mathbf{8}}$

Hope this information will clear your doubts about topic.