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if x=-1/3 is a zero of the polynomial p(X)=27x³-ax²-x+3 then find the value of 'a'

The given polynomial is p(x)=27x³-ax²-x+3

$t h e r e f o r e, p (\frac{- 1}{3}) = 0 \Rightarrow 27 {(\frac{- 1}{3})}^{3} - a {(\frac{- 1}{3})}^{2} - (\frac{- 1}{3}) + 3 = 0 [∵ x = \frac{- 1}{3} i s a z e r o o f p (x) \Rightarrow p (\frac{- 1}{3}) = 0] \Rightarrow 27 * \frac{- 1}{27} - \frac{a}{9} + \frac{1}{3} + 3 = 0 \Rightarrow - 1 - \frac{a}{9} + \frac{1}{3} + 3 = 0 \Rightarrow - \frac{a}{9} + \frac{- 3 + 1 + 9}{3} = 0 \Rightarrow - \frac{a}{9} + \frac{7}{3} = 0 \Rightarrow - \frac{a}{9} = - \frac{7}{3} \Rightarrow a = \frac{7}{3} * 9 \Rightarrow a = 21$

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