if x=-1, and y=2 in a solution of kx+3y=7,find the value k.

putting in x=-1 and y=2 in the equation

k(-1)+3(2)=7

-k+6=7

-k=7-6

-k=1

k=-(1)

therefore, k=-1 ANS

  • 6

by putting value of x and y

we have, k(-1) + 3(2)=7

-k+6=7

-k=1

k=1-1

k=-1

  • 1

kx+3y=7

now put x=-1,y=2

then k(-1)+3(2)=7

-1k+6=7

-1k=7-6

-1k=1

k=1/-1

k=-1

  • 0
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