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if x = {3/2} power 2 * {2/3} power -4 ,find the value of x to the power -2.

$x = {(\frac{3}{2})}^{2} \times {(\frac{2}{3})}^{- 4} \Rightarrow x = {(\frac{3}{2})}^{2} \times \frac{1}{{(\frac{2}{3})}^{4}} \Rightarrow x = {(\frac{3}{2})}^{2} \times {(\frac{3}{2})}^{4} \Rightarrow x = {(\frac{3}{2})}^{6} s q u a r i n g o n b o t h s i d e s, w e h a v e, x^{2} = {[{(\frac{3}{2})}^{6}]}^{2} = {(\frac{3}{2})}^{12} \Rightarrow \frac{1}{x^{2}} = \frac{1}{{(\frac{3}{2})}^{12}} \Rightarrow x^{- 2} = {(\frac{2}{3})}^{12} H e n c e, t h e v a l u e o f x^{- 2} i s {(\frac{2}{3})}^{12} .$

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