In a circle of diameter 60 cm the length of a chord is 30 cm. Find the length of the minor and the major arcs of the chord. { hint: Triangle OAB being equilateral theta=60 degrees=pie/3 rad

Now minor arc AB=r theta

Also major arc = 2 pie r - minor arc}

And length of the chord is 30cm

Hence angle BOA = 60

So minor arc length is given by $\theta =\frac{l}{r}$

Here l is the arc length and r is radius.

So r = 30 and $\theta =\frac{\mathrm{\pi}}{3}$

So l = 30pi/3 = 10pi

And major arc has angle as 5pi/3

So major arc length = 50pi

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