In a circle of diameter 60 cm the length of a chord is 30 cm. Find the length of the minor and the major arcs of the chord. { hint: Triangle OAB being equilateral theta=60 degrees=pie/3 rad
Now minor arc AB=r theta
Also major arc = 2 pie r - minor arc}
Radius of the circle is 30cm
And length of the chord is 30cm
Hence angle BOA = 60
So minor arc length is given by
Here l is the arc length and r is radius.
So r = 30 and
So l = 30pi/3 = 10pi
And major arc has angle as 5pi/3
So major arc length = 50pi
And length of the chord is 30cm
Hence angle BOA = 60
So minor arc length is given by
Here l is the arc length and r is radius.
So r = 30 and
So l = 30pi/3 = 10pi
And major arc has angle as 5pi/3
So major arc length = 50pi