in a figure,a circle is inscribed in a square of side 4cm and another ciccle is circumscribing the square.Proove that the area of the circumscribed ciccle is two times the area of the inscribed circle.
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ABCD is a square of side 4 cm.
Let r and R be the radius of the inscribed and circumscribed circle respectively.
Diameter of the inscribed circle = 2r
∴ 2r = 4 cm.
⇒ r = 2 cm.
Diameter of the circumscribed circle = Length of diagonal of the square
∴ Area of circumscribed circle = 2 × Area of inscribed circle