in a figure,a circle is inscribed in a square of side 4cm and another ciccle is circumscribing the square.Proove that the area of the circumscribed ciccle is two times the area of the inscribed circle.

please i want the answer too fast!its an emergency.

ABCD is a square of side 4 cm.

Let r and R be the radius of the inscribed and circumscribed circle respectively.

Diameter of the inscribed circle = 2r

∴ 2r = 4 cm.

r = 2 cm.

Diameter of the circumscribed circle = Length of diagonal of the square

∴ Area of circumscribed circle = 2 × Area of inscribed circle

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