in a quadrilateral ABCD, AB=BC & CD=DA then the quadrilateral is a
Let ABCD be the quadrilateral in which diagonals AC and BD bisects each other.
Given that AB = BC and CD = DA.
According to the above conditions, ABCD is a rhombus because if the diagonals of a quadrilateral bisect each other, then it is a parallelogram and opposite sides of a parallelogram are equal.