In a rectangle ABCD , AB = 25 cm and BC = 15 cm . in what ratio does the bisector of angle C divide AB?
AB = 25 cm, BC = 15 cm
CE is the bisector of ∠C = ∠BCE = 45°
Therefore, ∠BEC = 45° {Angle sum property of a triangle]
BC = BE [Sides opposite to equal angles are equal]
BE = 15 cm
AE = 25 - 15 = 10 cm
AE:BE = 10 : 15 = 2 : 3
Therefore, the ratio in which the bisector of ∠C divides AB is 2:3.
CE is the bisector of ∠C = ∠BCE = 45°
Therefore, ∠BEC = 45° {Angle sum property of a triangle]
BC = BE [Sides opposite to equal angles are equal]
BE = 15 cm
AE = 25 - 15 = 10 cm
AE:BE = 10 : 15 = 2 : 3
Therefore, the ratio in which the bisector of ∠C divides AB is 2:3.