In a series of LCR circuit R = 1000 ohm, C = 2muf and voltage across R = 100 V - Physics - Alternating Current

Question

In a series of LCR circuit R = 1000 ohm, C = 2muf and voltage
across R = 100 V The resonant frequency of the circuit omega is 200
rad/sec Calculate the value of voltage across L at resonance

Jegannathan Anandaraman · Accepted Answer

Hello Chaitra dear, at resonance the impedance will be only of
resistance i e R
So current at resonance = 100 / 1000 = 0 1 A
Capacitive reactance = Xc = 1/ w C
w = 200 rad/s and C = 2 * 10^-6 F
Plug and you get Xc = 1000000 / 400 = 2500 ohm
Hence voltage across capacitance = Xc * i = 2500 * 0 1 = 250 V
At resonance the voltage across Inductance will be the same as that
of capaacitance
Hence voltage across Inductance = 250 V

In a series of LCR circuit R = 1000 ohm, C = 2muf and voltage across R = 100 V. The resonant frequency of the circuit omega is 200 rad/sec.Calculate the value of voltage across L at resonance.