In a trapezium ABCD, AB is parallel to DC and DC = 2AB E is point on BC such that BE : EC = 3:4. EF is drawn parallel to AB where F is a point on AD . Prove that 7EF = 10AB.
ABCD is a trapezium. where . and
DC = 2 AB .......(1) and BE : EC = 3:4.............(2)
the triangles CGE and triangles CAB are similar triangles.
therefore ratio of corresponding sides are equal.
since , therefore
the triangles AFG and ADC are similar triangles.
adding eq(3) and eq(4):
which is the required result.
hope this helps you.