In a triangle ABC, 15<A= 10<B = 6<C. Find the three angles. Share with your friends Share 1 Varun.Rawat answered this Let ABC be the ∆.We have,15∠A = 10∠B = 6∠CLet 15∠A = 10∠B = 6∠C = kNow, ∠A = k15; ∠B = k10; ∠C = k6Now, ∠A + ∠B + ∠C = 180° Angle sum property⇒k15 + k10 + k6 = 180°⇒2k + 3k + 5k30 = 180°⇒10k30 = 180°⇒k = 540°now, ∠A = 540°15 = 36°Now, ∠B = 540°10 = 54°∠C = 540°6 = 90° 8 View Full Answer Anirudh Chauhan answered this i dont know -2 Amrit Lal answered this Given 15A = 10B = 6C Thus A = 6/15C and B = 6/10C So A : B : C = 6/15 : 6/10 : 1 A : B : C = 12 : 18 : 30 A : B : C = 2 : 3 : 5 A = 360 B = 540 C = 900 ANSWER 1