In a triangle ABC , AB =AC and D is a point on side AC , such that BC2=AC.CD . Prove that BD =BC . PLEASE HELP ME MERITNATION !!!
given:BC2=AC.CD,BC/AC=CD/BC AND AB=AC
TO PROVE=BD=BC
PROOF;
IN TRIANGLES ACB AND BCD
BC/AC=CD/BC (GIVEN)
ANGLE C=ANGLE C (COMMON)
THEN TRIANGLE ACB ~ TRIANGLE BCD
BD/AB=BC/AC
BD=BC (AB=AC)