in an isosceles triangle the base angles are equal and the vertex angle is twice of each base angle . find the measures of the angles of the triangle..[linear equation]

Solution:

Let us assume that the base angle of the isosceles triangle be a^{o}, then the vertex angle will be 2a^{o}.

As we know that the sum of three angles of a triangle equal to 180^{o}.

a + a + 2a = 180

4a = 180

a = 180/4 = 45^{o}.

Since the base angles are equal, then the base angles are 45^{o} each, the vertex angle will be 2 x 45^{o} = 90^{o}.

**Ans: Base angles: 45 ^{o} each Vertex angle: 90^{o}.**

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