In any triangle XYZ, the bisectors of the angles y and z meet at '0'. From a point 'O', OP perpendicular to YZ, OQ perpendicular to ZX AND OR perpendicular to XY respectively.Prove that OP=OQ=OR
Given: In any triangle XYZ, the bisectors of the angles y and z meet at O.
From a point 'O', OP perpendicular to YZ, OQ perpendicular to ZX and OR perpendicular to XY respectively.
To Prove: OP=OQ=OR
Proof:
In ΔYRO and ΔYPO,
∠RXO=∠PYO [because YO is the bisector of ∠Y]
∠YRO=∠YPO [ each equal to 90°]
YO = YO[common]
⇒OP = OR (cpct)...(i)
similarly,
In ΔZPO and ΔZQO,
⇒OP = OQ (cpct)....(ii)
and In
ΔXRO and ΔXQO,
⇒OQ = OR (cpct).....(iii)
from (i), (ii) and (iii) ,we get,
OP = OQ = OR
Hence the result.