In figure, if AB||CD, CD||EF, & x:y=5:4, find z.

In the figure, AB is parallel to EF,
Therefore, x+y = 180 (co-interior angles are supplementary)
Let x = 5a
Let y = 4a
x+y = 180
5a+4a = 180
      9a = 180
        a = 180/9 = 20 degrees
Therefore, x = 5a = 100 degrees
Since AB is parallel to CD,
x = z = 100 (alternate interior angles are equal)

Hope this helps!

  • 3
if ab ll cd and cd ll ef then ab ll ef
so x+y =180 ( interior angle on the same side of the transversal )
Now x=5a and y=4a so 5a+4a=180
so a=20 so x=100,y=80
x=z=100 (alternative interior angle)
  • 3
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