In figure, if AB||CD, CD||EF, & x:y=5:4, find z.
In the figure, AB is parallel to EF,
Therefore, x+y = 180 (co-interior angles are supplementary)
Let x = 5a
Let y = 4a
x+y = 180
5a+4a = 180
9a = 180
a = 180/9 = 20 degrees
Therefore, x = 5a = 100 degrees
Since AB is parallel to CD,
x = z = 100 (alternate interior angles are equal)
Hope this helps!
Therefore, x+y = 180 (co-interior angles are supplementary)
Let x = 5a
Let y = 4a
x+y = 180
5a+4a = 180
9a = 180
a = 180/9 = 20 degrees
Therefore, x = 5a = 100 degrees
Since AB is parallel to CD,
x = z = 100 (alternate interior angles are equal)
Hope this helps!