since the diagonals of a trapezium divide each other proportionally
we have,
OA/OC=OB/OD
X+5/X+3=X-1/X-2
(X+5)(X-2)=(X-1)(X+3) ------(CROSS MULTIPLICATION)
X2 -2X+5X-10 =X2 +3X-X-3
3X-2X=10-3
X=7

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Aman Bakhsh answered this

figure?

-1

Akshat Manas answered this

can't say

2

Saranya answered this

figure pls

5

Ashtalaxmi.guttedar answered this

The fig of the above question is

-4

Ashtalaxmi.guttedar answered this

The diagram of the above question is

-11

Anju Mahesh Suryavanshi answered this

cant, you give figure

-3

Vinit Shrivastava answered this

No you didn't give the figure how can we give the answer

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No answered this

Ao/oc=bo/od
x+5/x+3=x-1/x-2
(x+5)(x-2)=(x-1)(x+3)
x^-2x+5x-10=x^+3x-x-3
By transposing,,,
-10=-x-3
-x=-7
x=7

3

Pratik answered this

Ok

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Shraddha Khacharia Jagdishbhai answered this

Where is figure

-4

Sia answered this

X =30

0

Gudiya answered this

In the figure PQ parallel angle PAB= 70, angle ACS = 100. Determine angle ABC, angle BAC, angle CAQ

1

Piyush answered this

Figure plz

13

Pragati answered this

This is the figure of that question

1

Yesg answered this

Please provide answer me

1

Sanskrati answered this

Please find this answer

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Sharsti Dubey answered this

Ab||cd find x

0

Shravani Khandagale answered this

In the figure a b parallel CD determine the value of x

0

Israt Jahan answered this

In the given figure a b parallel CD then the value of x is