In given figure, triangle BDE and triangle BAC are isosceles triangles and AE=DC. What can you say about angle ADB and angle CEB? Plz experts answer quickly as is my exam

Dear Student ,
 
Please find below the solution to the asked query :

AE=DC    GivenSubtracting DE from both sidesAE-DE=DC-DEAD=CEIn ADB and CEBAD=CE           Proved Above AB=CB            Equal sides of isoscelles triangle BACBD=BE            Equal sides of isoscelles triangle BDEBy SSS congruency criterionADB  CEBADB=CEB               By CPCT
 
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angle ADB is equal to angle BEC by cpct
 
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ae-cd given
b-common
adb-bec
 
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