In HORSES, BLACK IS DEPENDANT UPON A DOMINANT GENE ,B, and chestnut upon its recessive allele, b,.The trotting gait is due to a dominant gene, T, the pacing gait to its recessive allele, t. If a homozygous black pacer is mated to a homozygous chestnut trotter, what will be the appearance of the F1 generation.
Please solve this genetics question.
Dear Student,
In this question we are given certain information
Black is dominant and defined by B
Chestnut is recessive and defined by b
Trotting is define by dominant T
Pacing is defined by recessive t
Now look at the condition given
We have
Homozygous black pacer which can be defined by BBtt
and
Homozygous chestnut trotter which can be defined by bbTT
If we cross these two organisms by Punnet square method we get.
So the F1 generation will be heterozygous Black Trotter
In this question we are given certain information
Black is dominant and defined by B
Chestnut is recessive and defined by b
Trotting is define by dominant T
Pacing is defined by recessive t
Now look at the condition given
We have
Homozygous black pacer which can be defined by BBtt
and
Homozygous chestnut trotter which can be defined by bbTT
If we cross these two organisms by Punnet square method we get.
So the F1 generation will be heterozygous Black Trotter