SEE IN MISSISSIPPI THERE R II LETTERS
NOW FOR FINDING NO OF WORDS IN WHICH ALL THE I'S R NOT TOGETHER= TOTAL PERMUTATION- NO OF WORDS FORMED HAVING ALL I'S TOGETHER
FOR TOTAL NO OF WORDS FORMED FROM MISSISSIPPI= 11 !/ 4!4!2! AS S REPEATS 4 TIMES , I
REPEATS 4 TIMES AND P REPEATS 2 TIMES = 34650
NOW WORDS HAVING ALL I'S TOGETHER
SEE WE will now consider the group of 4 I' as one only
so now there are only 8 letters remaining out of 11
thus words having all i's together will be 8! / 4! 2! = 840
now we will get no of words formed which will not have i's together= total- all i's together
= 34650 - 840 = 33810 words