In how many distinct permutations of the letter in "MISSISSIPPI" do the four I's not come together?

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 SEE IN MISSISSIPPI THERE R II LETTERS

NOW FOR FINDING NO OF WORDS IN WHICH ALL THE I'S R NOT TOGETHER= TOTAL PERMUTATION- NO OF WORDS FORMED HAVING ALL I'S TOGETHER

FOR TOTAL NO OF WORDS FORMED FROM MISSISSIPPI= 11 !/ 4!4!2!  AS S REPEATS 4 TIMES ,  I

REPEATS 4 TIMES AND P REPEATS 2 TIMES = 34650

NOW WORDS HAVING ALL I'S TOGETHER

SEE WE will now consider the group of 4 I' as one only

so now there are only 8 letters remaining out of 11 

thus words having all i's together will be 8! / 4! 2! = 840

now we will get no of words formed which will not have i's together= total- all i's together

  = 34650 - 840 = 33810 words 

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