In how many ways can 5girls and 3 boys be seated in a row so that no two boys are together
Here In the question, there are 5 girls. 5 girls can be seated in 5P5=5x4x3x2x1=5! ways. After arranging the girls in 5 ways, boy can sit in 6 places, as given below by $ sign:
$ G $ G$ G $ G $ G $
Now, the question says that no two boys can sit togerher. So there are 6 places where these 3 boys can sit. So now the boys can sit in 6P3.
Therefore, the total number of seating arrangements possible
=5P5 x 6P3
= 5 x 4 x 3 x 2 x 1 x 6 x 5 x 4 ways