In Ma2b2c2 type pls draw all geometrical, optical and stereoisomers. Actually I'm confused that if we change the order of a, b c in the compound then a new geometry is formed and that will also behave different to plane polarized light. So for this case we can arrange in 5 different orders of a2b2c2. So are all 5 optical isomers? And then if we take their mirror images then we'll Have 10 optical isomers as all 10 have diff rotation. So what is geometrical isomerism here?

Dear student
Please find the solution to the asked query:

To understand geometrical isomerism in a complex [Ma2b2c2] type, let us take the example of a complex
 [Cr((NH3)2(H2O)2(Br)2]+. This ion can theroretically exist in five geometrical isomers that are shown below.

the first isomer is the cis isomer since in this form two identical ligands lie occupying the adjacent positions and in the second form it is trans because two identical ligands are placed at opposite positions. The isomers c ,d and e are obtained when the ligands of one type are trans to each other and the remaining ligands are cis to each other.

The cis isomer shown in d is optically active so it exists as d and l isomer .
This ,means that a complex of this type has 7 isomers out of which 5 are geometrical and 2 are optical isomers.

Hope this information will clear your doubts regarding the topic. If you have any other doubts please ask here on the forum and our experts will try to solve them as soon as possible.


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