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In RD Sharma Chapter 15 : Areas related to circles: Revision exercise Question 32, how is the radius of the circle with centre C ,1/6th of AB ..???

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  • -7
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Hey, actually at first I also had the same problem, but later on I found out the answer. You need to do some sort of constructions in that ques.

1. Join C with the centres of any of the semi-circles drawn on AM MB and then join CM.

Now, CM is the tangent to semi-circle AM or MB

=

Let the centre of semi-circle AM be X.

So, In triangle CMX,

= (CX)2 = (CM)2 + (MX)2

= (9+r)2 = (18-r)2 + (9)2 ( let radius of circle with cantre C be 'r' )

= On simplifying,

r = 6cm = AB/6.

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