In the adjoining figure. PQRS and PABC are two parallelogram of equal area. Prove that QC|| BR.


Extent B & R to D in which CB || SD & QR || AD.

Since PS || AD.
=> PC || BD (Parts of parallel sides are parallel)

Therefore, angle PCB = angle DBC (alternate angles)
(or) 1/2 angle PCB = 1/2 angle DBC
(or) angle QCB = angle RBC

Since angle QCB & angle RBC are alternate angles and they are equal, 
=> QC || BR
                          
                                                                                                              HENCE PROVED

 

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