In the adjoining figure. PQRS and PABC are two parallelogram of equal area. Prove that QC|| BR.
Extent B & R to D in which CB || SD & QR || AD.
Since PS || AD.
=> PC || BD (Parts of parallel sides are parallel)
Therefore, angle PCB = angle DBC (alternate angles)
(or) 1/2 angle PCB = 1/2 angle DBC
(or) angle QCB = angle RBC
Since angle QCB & angle RBC are alternate angles and they are equal,
=> QC || BR
HENCE PROVED