IN THE FIGURE AB = AC. PROVE THAT BD = BC
Dear Student,
Please find below the solution to the asked query:
Given : AB = AC , So from base angle theorem we get
ABC = ACB --- ( 1 )
And
BD = BC , So from base angle theorem we get
BDC = BCD --- ( 2 ) , ACB = BCD ( Same angles ) , So from equation 1 a nd w we get
ABC = ACB = BDC --- ( 3 )
From angle sum property in triangle we get in triangle ABC :
BAC + ABC + ACB = 180 , Substitute values and get
40 + ABC + ABC = 180
2 ABC = 140
ABC = 70 , So From equation 3 we get
ABC = ACB = BDC = 70
And
CBD = ABC - ABD = 70 - 30 = 40
And
ADB = 180 - ABD - BAD = 180 - 30 - 40 = 110
Hope this information will clear your doubts about Congruence of Triangles.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Given : AB = AC , So from base angle theorem we get
ABC = ACB --- ( 1 )
And
BD = BC , So from base angle theorem we get
BDC = BCD --- ( 2 ) , ACB = BCD ( Same angles ) , So from equation 1 a nd w we get
ABC = ACB = BDC --- ( 3 )
From angle sum property in triangle we get in triangle ABC :
BAC + ABC + ACB = 180 , Substitute values and get
40 + ABC + ABC = 180
2 ABC = 140
ABC = 70 , So From equation 3 we get
ABC = ACB = BDC = 70
And
CBD = ABC - ABD = 70 - 30 = 40
And
ADB = 180 - ABD - BAD = 180 - 30 - 40 = 110
Hope this information will clear your doubts about Congruence of Triangles.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards