#
In the figure, find the four angles A, B, C, D in the parallelogram ABCD.

^{o}

^{ }(angle sum property of triangle)

15a = 180

^{o}

a = 12

4a = 4 x 12 = 48

5a = 5 x 12 = 60

6a = 6 x 12 = 72

angle B = angle D (opposite sides of parallelogram)

72

^{o}= angle D

angle D + angle A = 180

^{o}(adjacent angles of parallelogram )

72 + angle A = 180

^{o}

angle A = 108

^{o}

angle A = angle C

108

^{o}

^{ }= angle C

Therefore,

Angle A = 108

^{o}

Angle B = 72

^{o}

Angle C = 108

^{o}

Angle D = 72

^{o}

**
**