In the figure of the given construction if (triangle)QST (is similar to) (triangle) QRP, then QT:QP is ?

(A) 2:1 (B) 2:3 (C) 1:2 (D) 3:2 ?

Here

$\frac{QS}{QR}=\frac{QT}{QP}\phantom{\rule{0ex}{0ex}}Now\frac{QS}{QR}=\frac{3}{4}[fromthediagram].\phantom{\rule{0ex}{0ex}}\Rightarrow \frac{QT}{QP}=\frac{3}{4}$

Hope this would have cleared your doubt.

**
**