In the figure , OS is perpendicular to the chord PQ of a circle whose centre is O. if QR is a diameter ,show that QP=2OS.

With the given conditions, it is not possible to prove that QP = 2OS.

We can just prove that PR = 2OS.


O is the mid point of QR      (since O is the center of circle)

Also, S is the mid point of PQ.  (radius perpendicular to chord bisects the chord)

Now, using mid point theorem,

We can say that OS =

So, please recheck your query and do get back to us.

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