In the figure , OS is perpendicular to the chord PQ of a circle whose centre is O. if QR is a diameter ,show that QP=2OS.
With the given conditions, it is not possible to prove that QP = 2OS.
We can just prove that PR = 2OS.
O is the mid point of QR (since O is the center of circle)
Also, S is the mid point of PQ. (radius perpendicular to chord bisects the chord)
Now, using mid point theorem,
We can say that OS =
So, please recheck your query and do get back to us.