in the figure ,PQ=QR,if <QPR=55 degree,Find <TSR Share with your friends Share 6 Anuradha Sharma answered this Here PQ = QRSO angle QRP = 55So in triangle PQR, Angle PQR = 180-55-55=70 degreeNow opposite angle in cyclic quadrilateral are supplementary so angle ASR = 180-70=110 degreeSo using linear pair , angle RST+angle ASR=180So angle RST=180-110=70 degree 3 View Full Answer
