In the figure shown, a particle is released from the position A on a smooth track. When the particle reaches at B, then normal reaction on it by the track is:- a) mg b) 2mg c) 2mg/3 d) m2g/h Share with your friends Share 26 Vara answered this Sliding of the block:PE at the top=KE at the bottommg3h=12mv2v2=6ghMotion along the circle:KE at the bottom=KE+PE at the top12mv2=12mv'2+mg2hmv2=mv'2+4mghv2=v'2+4gh6gh=v'2+4ghv'2=2ghv'=2ghNormal reaction:R=mv'2r-mg =m2ghh-mg =mg 66 View Full Answer