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In the give figure, ABCD is a quadrilateral and AEDF is a parallelogram. AE and DE are the bisectors of DAB and ADC respectively.

What is the measure of AFD in the given figure?

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, ABCD is quadrilateral, the sum of angles is 360∠A+∠B+∠C+∠D = 360°x+x+110°+64°+y+y = 3602x + 2y = 360 - (110+64)2x+2y = 186x + y = 93-----------(1)In △AED, by angle sum property of trianglex + y +∠AED = 180°∠AED = 180 - 93 = 87°------(using 1)In parallelogram AFDE, ∠AED =∠AFD = 87°  (opoosite angles are equal)

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the measure of the angle DAB=180-110=70

so the measure of angleDAE=70/2=35

measure of ADC=180-64=116

and ADE=116/2=58

so AED=180-58+35=87

ar(AFD)=ar(AED)

so AFD = 87

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SORRY THIS ANS. IS RIGHT=AED=180-58+35=85

SO AFD = 87

PLZZ. THUMB UP..

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in quad.

angle A+B+C+D=360

angle A+D=360-174=186

DAE+ADE=1/2*186=93

AED=180-93=87

AFD=AED=87

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