In the given circuit diagram , the cell and ammeter, both have negligible resistance. The resistances are identical. With the switch 'k' open, the ammeter reads 0.6A. What will be the ammeter reading when the switch is closed?

Dear Student,

Let the value of each resistance be R1 When key K is open the only two resistance are in a circuit.So resultant resistance, in this case, is the parallel combination of two resistances.1R1=1R+1R=2RR1=R2Let potential difference of cell=V voltcurrent, I=0.6 AV=IR1V=0.6×R2=0.3 R

2 Now, when key K is closed, all three resistances are parallel in the circuit.Therefore,1R2=1R+1R+1R=3RR2=R3using ohm's law,V=IR20.3R=I×R3I=0.9 A

Regards

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