In the given circuit , R= 1ohm and ammeter shows reading of 7 A ,Find V . Share with your friends Share 0 Vaibhav T. answered this Dear Student, In triangle BFC, R2 and R3 are in series,r1=R2+R3r1=1+1=2 ohmNow, r1 is in parallel with R4,1r2=1r1+1R41r2=12+11r2=23 ohmIn triangle BAG, R1 and R7 are in series,r3=R1+R7r3=1+1=2Now, r3 is in parallel with R6,1r4=1r3+1R61r4=12+11r4=23 ohmNow, r2 and r4 are connecting in series,r5=r2+r4r5=23+23r5=43 ohmAccording to figure, r5 is connecting in parallel with R5,1r6=1r5+1R51r6=34+111r6=3+44r6=47 ohmNow, r6 is connecting in series with R8,r=r6+R8r=47+1r=4+77r=117 ohmcurrent, I=7 AV=IrV=7×117=11 V 3 View Full Answer Zaid Manyar answered this I=V/R 1=V/7 1*7=V Therefore V=7 1 Romil answered this Sorry but answer is 11 0
1ohm and ammeter shows reading of 7 A ,Find V .