In the given figure, ABCD is a rhombus with AC = 16 cm and AB = 10 cm . What is the area of the rhombus ABCD ? Share with your friends Share 0 Lovina Kansal answered this Dear student Clearly,∠AOB=∠BOC=∠COD=∠DOA=90° ∵Diagonals are ⊥Also,AO=OC=162=8cm and OD=OB ∵Diagonals bisect each otherSo, By pythgoras theorem in △AOBAO2+OB2=AB2⇒OB2=AB2-AO2⇒OB2=102-82⇒OB2=100-64⇒OB2=36⇒OB=6cmSo, BD=2OB=2×6=12cmSo, Area of rhombus ABCD=12×AC×BD⇒ Area of rhombus ABCD=12×16×12⇒ Area of rhombus ABCD=96cm2 Regards 0 View Full Answer T.s. Harigovind answered this Please find this answer 1 Rohan Kumar answered this 96cms square is right answer 2 S.manasa answered this it is the correct answer.thank u so much. 0