In the given figure, if AB parallel to CD, CD parallel to EF, find the value of (y-x):(y+x)
given-
AB//CD
CD//EF
in // line AB and CD let PR the transversal
∠BPR + ∠DRP=1800 (co-interior ∠)
500 + y= 1800
y=1800-500
y=1300
now in // Lines CD and EF let ST the transversal
∠DST=∠ETS
1100=∠ETS
∠ETS=300+x
1100-300=x
x=800
y-x
y+x
=1300-800
1300+800
=500/2100
=5:21
AB//CD
CD//EF
in // line AB and CD let PR the transversal
∠BPR + ∠DRP=1800 (co-interior ∠)
500 + y= 1800
y=1800-500
y=1300
now in // Lines CD and EF let ST the transversal
∠DST=∠ETS
1100=∠ETS
∠ETS=300+x
1100-300=x
x=800
y-x
y+x
=1300-800
1300+800
=500/2100
=5:21