In the given figure, O is the centre and AE is the diameter of the semicircle
ABCDE. If AB = BC and AEC = 50, then find
(a) CBE (b) CDE (c) AOB. Prove that BO||CE.

HINT

construction join BE, AC,OC,OD

BCDE IS A CYCLIC QUADRILATERALS

(ANGLE) ACE =900

ANGLE SUM PROPOERTY (TRIANGLE) ACE (ANGLE) CAE=400

  • 2

istill don't get it please tell me the anser

  • -9

REMEMBER:ANGLE IN A SEMICIRCLE IS 90

  • -6

can't u guys jus prove it 
other than giving obvious advice

  • -5

< = ANGLE

let<BOA= X  

<COB = <BOA = X

AS EQUAL SEGMENT SUBTEND EQUAL ANGLE AT CENTRE

<BEA = <CEB= X/2 = 250 ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC

  • SO <AOB =500

<OCE = 500 ISOSCELES TRIANGLE

BY ANGLE SUM PROPERTY <COE = 800

  • <CBE = 400 ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC
  • <CDE = 1400 AS BCDE IS A CYCLIC QUARDILATERAL
  • <BOC = <OCE = 500 AS WE HAVE PROVED AND BY ANLTERNATE INTERIOR PROPERTY BO|| CE

HOPE HELPED U TO PROVE WHOLE ANSWER

PLEASE PROVIDE YOUR EMAIL ID FOR DIAGRAM

  • 6

CHEERS

  • -21

VIEW MY ANSWER ON MORE COMMENTS

  • -11

 hi patra i know this ques is from u like of maths

  • -9

 < = (ANGLE)

let<BOA= X  

<COB = <BOA = X

AS EQUAL SEGMENT SUBTEND EQUAL ANGLE AT CENTRE

<BEA = <CEB= X/2 = 250 ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC

  • SO <AOB =500

<OCE = 50(ISOSCELES TRIANGLE)

BY ANGLE SUM PROPERTY <COE = 800

  • <CBE = 40ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC
  • <CDE = 1400 AS BCDE IS A CYCLIC QUARDILATERAL
  • <BOC = <OCE = 500 AS WE HAVE PROVED AND BY ANLTERNATE INTERIOR PROPERTY BO|| CE
  • 14

< = ANGLE

let<BOA= X

<COB = <BOA = X

AS EQUAL SEGMENT SUBTEND EQUAL ANGLE AT CENTRE

<BEA = <CEB= X/2 = 250 ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC

  • SO <AOB =500

<OCE = 500 ISOSCELES TRIANGLE

BY ANGLE SUM PROPERTY <COE = 800

  • <CBE = 400 ANGLE SUBTENDED AT CENTRE IS DOUBLE ANGLE SUBTENDED AT CERCUMFERENCE BY SAME ARC
  • <CDE = 1400 AS BCDE IS A CYCLIC QUARDILATERAL
  • <BOC = <OCE = 500 AS WE HAVE PROVED AND BY ANLTERNATE INTERIOR PROPERTY BO|| CE

HOPE HELPED U TO PROVE WHOLE ANSWER

PLEASE PROVIDE YOUR EMAIL ID FOR DIAGRAM

  • -9

 i dont know this answer is from ulike or not but i tried to solve it myself

  • -4

good well done my friend tujhse yahi umeed thi

  • -10
i still  cant understand. cant you just take a picture of the sum and post it. :p
 
  • 0
a- ABCE , 180-50=130-90=40
b-BCDR , 180-40=140
c-100?2 =50
d- corresponding angle are equal
  • -5
can some one please give a proper answer for this with a diagram??
  • -3
is the diagram wrong for this question????
 
  • 0
This is the pic of the question

  • -3
R450r 7ut86
  • -2
Above should be correct
  • -2
What are you looking for?