in the given figure o is the centre of the circle. if angle aob is 150 and angle oac is 40. Find angle acb and angle obc Share with your friends Share 1 Lovina Kansal answered this Dear student Given ∠AOB=150° and ∠OAC=40°To find ∠ACB and ∠OBCThe angle subtended by an arc of a circle at the centre is double the angle subtended by it at any point on the remaining part of the circle∠ACB=12reflex∠AOB=12360°-150°=105°Now we know that in a quadrilateral sum of all the angles is 360°ie ∠OAC+∠ACB+∠CBO+∠BOA=360°⇒∠CBO=360°-40°-105°-150°⇒∠CBO=65° Regards -2 View Full Answer Anima Thakur answered this 155 degree 0 Yatharth Patel answered this Angle ACB= 360-150 = 210/2 = 105 Angle OBC = 360 - [ 150+105+40 ] = 360- 295 = 65 1